![]() |
|
Camaro Parts at SS396.com GROUND UP & SS396.com Official Sponsor of Team Camaro |
|
||
| Team Camaro Tech Current Topic: Chevy 355????? | ||
Registered users (free) do not see these large ads 
| Tech 2001 General Tech questions from 2001 Replies ONLY, no new topics. |
![]() |
|
|
Thread Tools | Search this Thread | Display Modes |
|
#1
|
|||
|
|||
|
Ok...guys this may sound stupid but what exactly is a chevy 355...Also approx what kind of hp can a 355 with a blower put out...is 500-600 streetable hp obtainable with this set up....Thanks in advance
[This message has been edited by Badcaiman (edited 08-27-2001).] |
|
#2
|
|||
|
|||
|
I think a 350 bored .30 over
|
|
#3
|
|||
|
|||
|
My 355 makes 437 rear wheel horsepower (around 500 flywheel hp) with an ATI Procharger pushing 9 PSI of boost thru a set of mildly ported L98 (Corvette) aluminum heads. So, the answer to your question is, yes, it is possible.
------------------ Pearl blue & white 69 Camaro with supercharged 350, Tremec TKO, and 3.73 12-bolt See my website updated 4/16/01 at: www.geocities.com/gheatly |
|
#4
|
|||
|
|||
|
A bored .03 over 350 would become a 355 in3(albeit slightly lower compression unless you shave the heads a tad. Did it to mine, with the cam from a 327, 375 HP - just got the carb straightened out, AWESOME!!
JJH |
|
#5
|
|||
|
|||
|
You can find out the size of a motor by this formula:
Multiply: BORE x STROKE x PI x # of CYLINDERS by the way PI alway = 3.14 [This message has been edited by Black 67 (edited 08-29-2001).] |
|
#6
|
|||
|
|||
|
I thought it was:
Bore x Bore x Stroke x 3.1416 x # of cylinders ------------------ TONY 67 CAMARO R/S CLONE, 355/turbo 350, 200hp NOS,12 bolt,etc... |
|
#7
|
|||
|
|||
|
Lets do a Chevy 350
Multiply Below Bore 4.00 Stroke 3.48 Pi 3.14 Cylinders: 8 ---- 349.67ci. [This message has been edited by Black 67 (edited 08-29-2001).] |
|
#8
|
|||
|
|||
|
Don't want to get into a mathamatical feud, but BORE X PI X STROKE X #CYL, only works for 4" bore. The correct formula is 1/2BORE X 1/2BORE X PI X STROKE X #CYL.
It works for 4" because 1/2 x 4 x 1/2 x 4 = 4. |
|
#9
|
|||
|
|||
|
I don't want one either! I also do not claim to be a math whiz (not yet anyways but I am working on that) I was just trying to recall what was taught at the class that I took last semester out here.
The formula in our book is: CID= pie x R(squared) x L x N in which pie = 3.1416 R(squared) = bore radius or bore diameter/2 L = length of stroke N = number of cylinders This is were I have gotten my info. "Like I said that is what I thought, I have been wrong before and will be again!" ------------------ TONY 67 CAMARO R/S CLONE, 355/turbo 350, 200hp NOS,12 bolt,etc... [This message has been edited by idoxlr8 (edited 08-28-2001).] |
|
#10
|
|||
|
|||
|
to figure out the volume of a cylinder, you need diameter squared x pie x height. so that would equal bore squared (bore x bore) x 3.14 x stroke x number of cylinders.
[This message has been edited by lil_beast_67 (edited 08-28-2001).] |
|
#11
|
|||
|
|||
|
Bore x Bore x stroke x .7854 x # of cylinders...works every time
![]() Byt he way, overboring an engine, with all else the same, increases compression, not decreases it. ------------------ 375hp 78 Chevy truck 77 Chevy Nova 95 Chevy Lumina 3.4L and building a 78 Nova |
|
#12
|
|||
|
|||
|
I may be the oldest ( or nearly the oldest) poster here, but way back in the old days I was taught that the area of a circle was calculated with the formula " Pi r2 ". Now if that is the area of a circle, then multiplying this formula buy the height of the cylinder will give the volume of the cylinder. That is "Pi r2 h ". This is the same as 3.14 x 1/2d x 1/2d x height. End of math class.
H-dog |
|
#13
|
|||
|
|||
|
the formula Travis posted works in every case regardless of engine dimensions.
bore x bore x .7854 x stroke x # cylinders |
|
#14
|
|||
|
|||
|
UNREAL:
Man I've been out of school for to long... Thanks for showing me why it only works with a 4 inch bore... I still can't believe I forgot the formula... Oh well.. |
|
#15
|
|||
|
|||
|
H-dog, pie r round, cornbread r square!!
![]() My last year of college I had to take Chemistry 101 as a required class. In the first lab we were learning how to calculate volume (duh-pretty simple task after 4 years of engineering classes) and we each had to take an object from a box, measure it, and calculate its volume. I chose a cylinder because I was lazy and only wanted to measure 2 dimensions. But our worksheet had spaces for length, width, and height. I only filled in two: diameter and height, then calculated the volume. When I handed it in, the TA pointed out that one of the spaces was blank. I explained that I had a cylinder and only needed 2 dimensions to calculate the volume. She began to argue with me that it wasn't possible and I needed a third dimension to find the volume of a cylinder!!! And this girl was a grad student?? I realized on the first day that I wasn't going to get much out of that lab class. The second class she came over and apologized and agreed that I was right, you can find the volume of a cylinder with just diameter and height. ![]() Another way of looking at displacement (sometimes it helps me to derive a formula so I understand where it's coming from): Find the area of the cylinder: (bore)x(bore)x(PI)/(4) or (1/2 bore)x(1/2 bore)x(PI) (same thing different way) Then multiply by height of cylinder (stroke): (bore)x(bore)x(PI)/(4)x(stroke) or (1/2 bore)x(1/2 bore)x(PI)x(stroke) Then multiply by the number of cylinders to find the total displacement of the engine: (bore)x(bore)x(PI)/(4)x(stroke)x(# cyl) or (1/2 bore)x(1/2 bore)x(PI)x(stroke)x(# cyl) Note that the first equation is the same as Travis' because PI/4 = .7854 [This message has been edited by No 'E' in Camaro (edited 08-29-2001).] |
|
|
|
|
![]() |
| Thread Tools | Search this Thread |
| Display Modes | |
|
|