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hallo guys can anyone explain me how to calculate tire and rim size thanks fore the information
 

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Tire size = 275/60/15

275 is mm and is divided by 25.4 to convert to inches =(10.8")
60 is the aspect so 10.8 multiplied by .60 =(6.5")
2 sides so add together =(12.99")
now add the rim diameter =(27.99")

So that tire would be 10.8" wide (just over 10 3/4) by 28" tall.
 

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Ladies and Gents and the rest of you NOT in the mosh pit....
1968 camaro convertible with the ridetech tru turn 2" drop spindle set up and factory control arms, Wilwood Forged Narrow Superlite 6R Big Brake Front Brake six-piston calipers with 12.88" diameter, 1 piece rotor, stock rear mono leaf, 10 bolt drum.
Ridetech states i can fit up to a 18" x 10" wheel up front with a maximum back space of 5.75 and have read members have tucked 18" x 9.5" x 5.5" backspace rear with no suspension modifications.
I want to run 18 x 9.5 x 5.5 back space x 275 45 18 on all four corners. The :confused caliper overhang from rotor face is +.02 mm and total hub offset of +.38 mm vs original drums.(track width?)
My question : what would my min wheel offset need to be (pad height) in order to clear caliper yet clear outer fender inner lip edge. Why min wheel offset? Like the look of wheel lip (deep dish) I have no reservations of rolling fender inner lip to accommodate.
I would like the luxury of rotating wheels / tires front to back for longevity. Any info would be greatly appreciated.:confused:
 
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